Answer:
Diameter of the circle K = 20 units
Explanation:
Given that : EF = HG
Also, HG = 16 units
⇒ EF = 16 units
Now, any line drawn perpendicular to the chord always bisects the chord
⇒ KI will bisect the chord EF
⇒ EI = 8 units
Now, in ΔEIK using Pythagoras theorem we have :
⇒ EK² = 8² + 6²
⇒ EK² = 100
⇒ EK = 10 units
So, Radius of the circle K = 10 units
Now, Diameter of the circle K = 2 × 10
= 20 units