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41 votes
41 votes
Set y=0 and apply the zero product property
y = x {}^(2) + 2x - 3

User Oktieh
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1 Answer

18 votes
18 votes

Given:


y=x^2+2x-3
\begin{gathered} 0=x^2+2x-3 \\ 0=x^2-x+3x-3 \\ 0=x(x-1)+3(x-1) \\ 0=(x-1)(x+3) \end{gathered}
x=1,-3

User Tom Wells
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