Question

Assuming that the smallest measurable wavelength in an experiment is 0.370 fm , what is the maximum mass of an object traveling at 577 m⋅s−1 for which the de Broglie wavelength is observable?

Answer 1

mass = 3.104x10^-21 kg

Step-by-step explanation:

de Brogile wavelength = h/mv h= Planck's constant = 6.626x10^-34

1 fm = 1x10^-15 m

0.370x10^-15 m = 6.626x10^-34/(mass x 577)

mass = 6.626x10^-34/(0.370x10^-15 x 577)

mass = 3.104x10^-21 kg