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Need help finding the meters to the question law of cosine

Need help finding the meters to the question law of cosine-example-1
User ZeroTek
by
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1 Answer

30 votes
30 votes

Answer:

242.7

Step-by-step explanation:

The law of cosines says that if we have tirangle of the form

then


c^2=a^2+b^2-2ab\cos C

now in our case a = 254, b = 102, and C = 72; therefore, the above equation gives


c^2=254^2+102^2-2(254)(102)\cos 72^o

which gives


c^2=74920-51816\cos 72^o
c^2=74920-16012.02458
c^2=58907.96

taking the square root of both sides gives


c=\sqrt[]{58907.96}
c=242.7

which is our answer!

Need help finding the meters to the question law of cosine-example-1
User Pic Mickael
by
3.4k points
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