Question

A golf ball is hit off the ground with a speed of 34.0 m/s at a 56.0° angle with the horizontal. If thea. How high (in meters) does the ball rise?b. If the ball lands on the ground at the same height that it was hit, how much time does the ball spend in the air?c. How many meters away does the ball land?

Answer 1

a)The golf ball is a projectile. We would calculate the maximum height of the ball by applying formula,

H = V^2Sin^2θ/2g

where

V is the velocity speed of the ball

g is acceleration due to gravity

H is the maximum height

θ is the angle fomred with the ground

From the information given,

V = 34

θ = 56

g = 9.81

By substituting these values into the formula, we have

H = 34^2Sin^56/2 * 9.81 = 40.495

The height of the ball is 40 m

b) We would apply the formula for calculating time of flight for projectiles which is expressed as

T = 2VSinθ/g

By substituting the values into the formula, it becomes

T = 2 x 34 x Sin56/9.81 = 5.75

The time spent by the ball in the air is 5.75 seconds

c) We would apply the formula for calculating range for projectiles which is expressed as

Range = V^2Sin2θ/g

By substituting the values into the formula, it becomes

Range = 34^2Sin(2 * 56)/9.81 = 109.26

Distance = 109 m