Question

Rubbing alcohol is 70.% isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a 1 pint (473 ml) container?

Answer 1

VC3H8O=330 mL 473*70/100=331.1 off two sig figs and it 330

Answer 2

Hello!

Rubbing alcohol is 70.0% isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a full 1 pint (473 ml) container?

We have the following information:

% V/V (percentage of volume per volume) = 70

V1 (solute volume) = ? (in mL)

V (volume of the solution) = 473 mL

We apply the data to the formula of volume percentage of the solute per volume of solution, we will have:

`\%\:v/v = (v_1)/(v) *100`

`70 = (v_1)/(473)*100`

`70*473 = 100*v_1`

`33110 = 100\:v_1`

`100\:v_1 = 33110`

`v_1 = (3311\diagup\!\!\!\!0)/(10\diagup\!\!\!\!0)`

`\boxed{\boxed{v_1 = 331.1\:mL\:of\:isopropyl\:alcohol}}\Longleftarrow(solute\:volume)\:\:\:\:\:\:\bf\purple{\checkmark}`

Answer:

331.1 ml of isopropyl alcohol

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