Question

QuestionIn ABC, C = 64°, c = 32, and b = 33. What are the two possible values for angle B to the nearest tenth of a degree?Select both correct answers.

Answer 1

Two possible diagrams of the triangle are shown below

To find angle B in each triangle, we would apply the law of sines which is expressed as

a/SinA = b/SinB = c/SinC

For either of the triangles, by applying the sine law, we have

33/Sin B = 32/Sin 64

By crossmultiplying, we have

32 SinB = 33 Sin 64

Sin B = (33 Sin 64)/32 = 0.9269

We would find angle B by finding the inverse of sine 0.9269

Thus,

B = Sin^-1(0.9269) = 68

This is an acute angle. B can also be an obtuse angle. Greater than 90 but less than 180 degrees). Thus, another value for B is