Question

Find the real or imaginary solutions of the equation by factoring. X^4-10x^2=-9

Answer 1

`x^4-10x^2=-9`


`x^4-10x^4+9=0`


Let
`x^2` be
`A`

Therefore,


`A^2-10A+9=0`

Through quadratic factoring,


`(A-9)(A-1)=0`


`A=1,9`

Resubstitute for
`x`.


`x^2=1`


`x=<span>1,-1`

and,


`x^2=9`


`x=</span><span>3,-3`