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Find the real or imaginary solutions of the equation by factoring. X^4-10x^2=-9

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x^4-10x^2=-9


x^4-10x^4+9=0


Let
x^2 be
A

Therefore,


A^2-10A+9=0

Through quadratic factoring,


(A-9)(A-1)=0


A=1,9

Resubstitute for
x.


x^2=1


x=<span>1,-1

and,


x^2=9


x=</span><span>3,-3
User Bill Ticehurst
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