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What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?k = a0
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What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?k = a0

User Nigel Ren
by
8.0k points

2 Answers

7 votes

Answer:

3

Explanation:

the answer is 3

User Arthur Silva
by
9.0k points
6 votes
f(x) = 112 - kx
f(-3) = 121

f(-3) = 112 - k(-3)
f(-3) = 112 + 3k
121 = 112 + 3k
121 - 112 = 3k
9 = 3k
9/3 = k
3 = k <===
User Shereen
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8.3k points
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