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A city is growing at the rate of 0.3% annually. If there were 3,278,000 residents in the city in 2015, find how many (to the nearest ten-thousand) are living in that city in 2021. Use y = 3,278,000(2.7)0.003t , where t represents the number of years since 2015.

User ROrlig
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2 Answers

3 votes
The formula is
A=pe^rt
A ?
P 3,278,000
E constant, it equals 2.7
R 0.003
T 2,021−2,015=6 years

A=3,278,000×e^(0.003×6)
A=3,337,538
User Grifball
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6.6k points
3 votes

Answer:

3330448

Explanation:

We must evaluate the population from 2015 to 2021 to the nearest ten-thousand. Using the following expression:


y=3278000*(2.17)^0.003*t

where t represents the number of years since 2015 and 2.17 is the logarithmic function e. The number of years since 2015 to 2021 is 7 years.Substitue t=7 into the expression:


y=3278000*(2.17)^0.003*(7)=3278000*(1.016)=3330448

User Michael Sharek
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7.5k points