Question

Question 8 (1 point)

Use coefficients to balance the following reaction:
H2CO3 + Fe → Fe2(CO3)3 + H2
Blank 1:
Blank 2:
Blank 3:
Blank 4:

Answer 1

1) 3 2) 2 3) 1 4) 3

Step-by-step explanation:

so on the reactant side (left), there is 2 H, 1 CO3, and 1 Fe. On the product side (right) there is 2 Fe, 3 CO3, and 2 H2. So to start I added a 3 in the first blank to make CO3 equal on both sides. In doing this, there is not 2 H, there is now 6 so I added a 3 in the 4th blank. Currently, H and CO3 are equal on both sides but not Fe. So I added a 2 in the 2nd blank. I didn't add anything in the 3rd blank so it is an understood 1.

Answer 2

The balanced equation

3H₂CO₃ + 2Fe → Fe₂(CO₃)₃ + 3H₂

Further explanation

Given

Reaction

H₂CO₃ + Fe → Fe₂(CO₃)₃ + H₂

Required

Coefficient of the reaction

Solution

• Give a coefficient(the most complex = 1)

aH₂CO₃ + bFe → Fe₂(CO₃)₃ + cH₂

• Make an equation

Prioritize balancing the elements that form the most complex compounds

Fe, left = b, right = 2⇒b=2

C, left = a, right = 3⇒a=3

H, left = 2a, right = 2c⇒2a=2c⇒2.3=2c⇒6=2c⇒c=3

The equation becomes :

3H₂CO₃ + 2Fe → Fe₂(CO₃)₃ + 3H₂