Let a, b be two odd integers. Then both can be written as
a=2k-1, k is an integer
b=2m-1, m is an integer
So,
a-b=2k-1-(2m-1)=2k-2m-2=2(k-m-1)
Since, k and m and 1 are all integers, then (k-m-1) is also an integer. Hence, 2(k-m-1) is an even integer.
Thus, a-b is even.