Question

Bananas are sold in bunches at a grocery store and typically consist of 4-8 bananas per bunch. suppose the weight of these bunches follows a normal distribution with a mean of 3.54 pounds and a standard deviation of 0.63 pounds. what is the probability that a randomly selected bunch of bananas will weigh more than 3.0 pounds

Answer 1

Let me see.

Explanation:

you just gotta divide

Answer 2

Normal distribution
μ=3.54
σ=0.63
x≥3.0

Z(X≤x)=(x-μ)/σ=(3-3.54)/0.63=-0.85714
P(X≤x)=0.195683
P(X≥x)=1-P(X≤x)=1-0.195683=0.80432