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How many moles of AgNO3 are present in 1.50 L of a 0.050 M solution?
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How many moles of AgNO3 are present in 1.50 L of a 0.050 M solution?

User Christin
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2 Answers

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c = n / V

n = c × V
n = 0,05 × 1,5 = 0,075[mol]

:-) ;-)
User Darren Willows
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1 vote
0.075 moles of AgNO3 is the answer ....
User Brett Allred
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