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Use the formula to evaluate the series 6+2+2\3+2\9+...+a6

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If the series goes on to 6 terms then,
(6(1-(1/3)^6))/(1-(1/3))=8.98765432099

For an infinite series with first term 6 and common ratio 1/3 the sum is 9.

User Nikhil Unni
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