Question

The length of a rectangle is two-fifths of its perimeter. if the width of the rectangle is 35 inches, what is its length in inches?

Answer 1

width = xlength = 4x Use the formula for the perimeter of a rectangle to solve for x: perimeter = 2(length) + 2(width)50 = 2(4x) + 2(x)50 = 8x + 2x50 = 10x5 = x The width (x) is 5 feet and the length (4x) is 20 feet.

Answer 2

Length = 140 inches.

Explanation:

Given : The length of a rectangle is two-fifths of its perimeter. if the width of the rectangle is 35 inches.

To find : what is its length in inches.

Solution : We have given

Length of rectangle = L.

Perimeter = P.

According to question

Length of a rectangle is two-fifths of its perimeter.

L =
`(2)/(5) * perimeter`.

L=
`(2)/(5) * perimeter`.

Width = 35 inches .

Perimeter = 2 ( length + breadth ) .

Plug the values of length =
`(2)/(5) * perimeter` ; Width = 35 inches .

Perimeter = 2 (
`(2)/(5) * perimeter` + 35).

P =
`(4)/(5) * P + 70` .

On subtracting from both side by
`(4)/(5) * P` .

P -
`(4)/(5) * P` = 70 .

`(5 P - 4P)/(5)` = 70 .

`(P)/(5)` = 70.

On multiplying both side by 5

P = 70 *5

P = 350 inches .

Now , Plug value of perimeter in Length.

Length =
`(2)/(5)* perimeter`.

Length =
`(2)/(5)* 350`.

Length = 140 inches.

Therefore, Length = 140 inches.