Question

How many fluorine atoms are present in 5.85 g of c2f4?

Answer 1

To find the number of fluorine atoms in 5.85 g of C2F4, calculate the number of moles of C2F4 and multiply by Avogadro's number and 4. There are approximately 1.41 × 10^23 fluorine atoms in 5.85 g of C2F4.

Step-by-step explanation:

To calculate the number of fluorine atoms in 5.85 g of C2F4, we first need to find the molar mass of C2F4. The molar mass can be determined by adding the masses of two carbon atoms and four fluorine atoms. Using the periodic table, the mass of carbon is 12.01 g/mol and the mass of fluorine is 19.00 g/mol. Therefore, the molar mass of C2F4 is (2 × 12.01) + (4 × 19.00) = 24.02 + 76 = 100.02 g/mol.

Next, we can calculate the number of moles of C2F4 in 5.85 g by dividing the mass by the molar mass:

Number of moles of C2F4 = 5.85 g ÷ 100.02 g/mol = 0.05848 mol

Since each molecule of C2F4 contains four fluorine atoms, we can then determine the total number of fluorine atoms:

Total number of fluorine atoms = number of moles of C2F4 × Avogadro's number × 4

Total number of fluorine atoms = 0.05848 mol × 6.022 × 10^23 mol^-1 × 4 = 1.41 × 10^23 atoms

Answer 2

The molar mass of C2F4 (tetrafluoroethylene) is equal to 100 g/mol. The number of moles of C2F4 in the given amount,
n = (5.85 g) / (100 g/mol) = 0.0585 mols C2F4
The number of molecules per mol is calculated through the equation,
(0.0585 mols) x (6.022 x 10^23)
Since there are 4 F atoms each molecule then,
(0.0585 mols) x (6.022 x 10^23)(4)
= 1.41 x 10^23 atoms of F