Question

What is y = -5/2 - 4 in standard form?

Answer 1

Answer:
`y=(2)/(5)x\text{ + 2}`Explanations:

The slope-intercept form of the equation of a line is:

y = mx + c

where m is the slope

and c is the y-intercept

The given equation is:

`y\text{ = -}(5)/(2)x\text{ - 4}`

Comparing the given equation with y = mx + c:

The slope, m = -5/2

The equation perpendicular to y = mx + c and passing through the point (x₁, y₁) is given by the equation:

`\text{y - y}_1=(-1)/(m)(x-x_1)`

Since m = -5/2

-1/m = 2/5

The line passes through the point (5, 4)

x₁ = 5, y₁ = 4

The equation becomes:

`\begin{gathered} y\text{ - 4 = }(2)/(5)(x\text{ - 5)} \\ y\text{ - 4 = }(2)/(5)x\text{ - 2} \\ \text{y = }(2)/(5)x\text{ - 2 + 4} \\ y=(2)/(5)x\text{ + 2} \end{gathered}`