Question

Consider the nuclear equation below.

What is the nuclide symbol of X?

A) 231/94 Pu
B) 235/90 Th
C) 239/94 Pu
D) 231/90 Th

Answer 1

²³⁵₉₂U → ²³¹₉₀Th + ⁴₂He

D) ²³¹₉₀Th

Answer 2

Answer;

D) ²³¹₉₀Th

Step-by-step explanation;

²³⁵₉₂U → ²³¹₉₀Th + ⁴₂He

This is known as alpha decay

Alpha decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and thereby transforms or 'decays' into a different atomic nucleus, with a mass number that is reduced by four and an atomic number that is reduced by two.