We are to find the equation of a line passing through the point (-3,3) and perpendicular to the line y = 1/5x.
First we need to get the slope of the given line. The slope is 1/5
Since the unknown line is perpendicular to the given line, the slope of the unknown line will be m = -1/(1/5)
m = -5
The point slope equation of a line is expressed as;
y - y0 = m(x-x0)
(x0, y0) = (-3, 3)
m = -5
Substitute into the formula;
y - 3 = -5(x-(-3))
y - 3 = -5(x+3)
y - 3 = -5x - 15
y = -5x - 15 + 3
y = -5x - 12
Hence the required equation is y = -5x - 12