1 Answer

Jatt · Answer 1 · 2023-02-22T13:26:36+0000

To find the derivatives we have to use the following property:

$(d(uv))/(dx)=u^(\prime)v+uv^(\prime)$

Then the first derivative will be:

$y\text{ = 2xe}^(-x)$

$y^(\prime)\text{ = }2\mleft(e^(-x)-e^(-x)x\mright)$

Now to find the second derivative we have to use the same derivative property with the part "-xe^-x. Thus:

$y^(\doubleprime)=2(-2e^(-x)+xe^(-x))$

Now we have to equal the equation to zero:

$e^(-x)(x-2)=0_{}$

The first solution will be:

$-x\text{ = ln 0}$

ln 0 is undefined, so this answer is impossible.

The second solution will be:

$x-2\text{ = 0}$

$x\text{ = 2}$

Answer: x = 2.

Your comment on this question: