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Suppose That the length of a certain rectangular is 1 meter more than 5 times it width. The perimeter of rectangular is 98 meters. Find the length and width

User Kvance
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1 Answer

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Let breadth(b) of rectangular be x
Then length(l) = 5x + 1
We have : perimeter(p) =2(l+b)
Or, p = 2 (5x+1+x)
p = 2 (6x+ 1)
p = 12x + 2
Given that p= 98 m
98=12x+2 i.e. x= 8
So breadth b= 8m and length l =5*8+1= 41m

User Kenco
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