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A battery delivering a current of 55.0 a to a circuit has a terminal voltage of 14.3 v. the electric power being dissipated by the internal resistance of the battery is 34 w. find the emf of the battery.

User Yoeli
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Let Vi be voltage drop of internal resistance. Then Vi•I=34W. Vi=34/55=0.618V. This is lost internally to the battery so the total voltage of the battery is 14.3V+0.618V=8.84V
User ThePhi
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