Question

Hola I only need help for that one and other 3 ones

Answer 1

The equation of a straight line in the slope-intercept form is given to be:

`y=mx+b`

where m is the slope of the line and b is the intercept on the y-axis.

The slope can be calculated using the formula:

`m=(y_2-y_1)/(x_2-x_1)`

From the graph, we can pick two points as shown below:

`\begin{gathered} (x_1,y_1)=(0,6) \\ (x_2,y_2)=(6,9) \end{gathered}`

Therefore, the slope of the line is calculated to be:

`m=(9-6)/(6-0)=(3)/(6)=(1)/(2)`

The y-intercept is the y-value when x = 0. Therefore, we have the y-intercept to be:

`b=6`

Therefore, the equation of the line is given to be:

`y=(1)/(2)x+6`