Question

How do you find all zeros for this equation if it can’t be factored though? f(x) = 2x^2 -12x+ 7

Answer 1

The zeros of the function are 5.35 and 0.65

Explanation:

We have the following function:

`f(x)=2x^2-12x+7`

We equal 0 and use the general formula of quadratic equations to calculate the zeros of the function, just like this:

`\begin{gathered} x_(1,\:2)=(-b\pm√(b^2-4ac))/(2a) \\ \\ a=2,\:b=-12,\:c=7 \\ \\ x_(1,\:2)=(-\left(-12\right)\pm √(\left(-12\right)^2-4\cdot \:2\cdot \:7))/(2\cdot \:2) \\ \\ x_(1,2)=(12\pm√(88))/(4) \\ \\ x_1=\:(12+√(88))/(4)\:=5.35 \\ \\ x_2=\:(12-√(88))/(4)\:=0.65 \end{gathered}`

Therefore, the zeros of the function are 5.35 and 0.65