Question

Solve the following system of equations,2x - 3y = 8-2x + 6y = -20

Answer 1

`\begin{gathered} x\text{ = -2} \\ y\text{ = -4} \end{gathered}`

Step-by-step explanation:

Here, we want to solve the system of linear equations

From the first equation, we have it that:

`2x\text{ = 8 + 3y}`

Substitute this into second equation, we have this as:

`\begin{gathered} -(8+3y)\text{ + 6y = 20} \\ -8-3y+6y\text{ = -20} \\ -8+3y\text{ = -20} \\ 3y\text{ = -20+8} \\ 3y\text{ = -12} \\ y\text{ = -}(12)/(3) \\ y\text{ = -4} \end{gathered}`

To get the value of x, we proceed to make a substitution into the equation we made from equation 1

That would be:

`\begin{gathered} 2x\text{ = 8 + 3(-4)} \\ 2x\text{ = 8-12} \\ 2x\text{ = -4} \\ x\text{ = -}(4)/(2) \\ x\text{ = -2} \end{gathered}`