Question

The second part of the problem is where i need help. The answers i have there have been given by other tutors

Answer 1

From the given value

Since

`\sin u=(7)/(25)`

Then using trigonometrical ratios it follows

`\cos u=(24)/(25)`

Using hal -ngle it folows

`\begin{gathered} sin((u)/(2))=\sqrt{(1-(24)/(25))/(2)} \\ s\imaginaryI n((u)/(2))=\sqrt{(1)/(50)} \end{gathered}`

Also

`\begin{gathered} cos((u)/(2))=\pm\sqrt{(1+(24)/(25))/(2)} \\ cos((u)/(2))=\sqrt{(49)/(50)} \\ cos((u)/(2))=7\sqrt{(1)/(50)} \end{gathered}`

Finally?

`\begin{gathered} \tan((u)/(2))=\pm\sqrt{(1-(24)/(25))/(1+(24)/(25))} \\ \tan((u)/(2))=\sqrt{(1)/(49)} \\ \tan((u)/(2))=(1)/(7) \end{gathered}`