Question

What is the molarity of a solution containing 56 grams of solute in 959 ml of solution? (molar mass of solute = 26 g/mol)?

Answer 1

26g --- 1 mol
56g --- X
X= 56/26 = 2,154 mol

959 ml = 959cm³ = 0,959dm³

C = n/V
C = 2,154/0,959
C = 2,246 mol/dm³

Answer 2

Answer: Molarity of solution will be 2.24 M.

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

`Molarity=(n* 1000)/(V_s)`

where,

n= moles of solute

`V_s` = volume of solution in ml = 959 ml

moles of solute =
`\frac{\text {given mass}}{\text {molar mass}}=(56g)/(26g/mol)=2.15moles`

Now put all the given values in the formula of molarity, we get

`Molarity=(2.15moles* 1000)/(959ml)=2.24mole/L`

Therefore, the molarity of solution will be 2.24 M.