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Sinx + cosx= 1 then find the value of x
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Sinx + cosx= 1 then find the value of x

User Shibapoo
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1√2sinx+1√2cosx=1√2. This can be written as cos(x−π4)=cos(π4) The general solution of this equation ls x−.π4=2nπ±π4,n=0,±1,±2,..., So, x=2nπandx=(4n+1)π2,n=0,±1,±2,±3.... ANSWER: x=2nπandx=(4n+1)π2,n=0,±1,±2,±3....



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