Question

The current size of an image on Sandra's computer is shown below:

A rectangle is shown. The length of the rectangle is labeled as length equal to 6 inches and the width is labeled as width equal to 8 inches.

What are the dimensions of the image at fraction 1 over 2 times its current size?

A. Length = 4 inches, width = 6 inches
B. Length = 3 inches, width = 4 inches
C. Length = 8 inches, width = 10 inches
D. Length = 12 inches, width = 16 inches

Answer 1

6*1/2=3
8*1/2=4
Length= 3 inches
width= 4 inches
Answer : B

Answer 2

Option B is correct

Length = 3 inches, width = 4 inches

Explanation:

As per the statement:

The current size of an image on Sandra's computer is shown below:

A rectangle is shown:

The length of the rectangle is labeled as length equal to 6 inches and the width is labeled as width equal to 8 inches.

⇒Length(l) = 6 inches and width(w) = 8 inches

We have to find the dimension of the image at fraction 1 over 2 times its current size.

Dimensions of the image at
`(1)/(2) * \text{Current Size}`

then;

`\text{Length} = (1)/(2) * \text{Current size of length}=(1)/(2) * 6 =3` inches

and

`\text{Width} = (1)/(2) * \text{Current size of width}=(1)/(2) * 8 =4` inches

Therefore, the dimensions of the image at fraction 1 over 2 times its current size are:

Length = 3 inches, width = 4 inches