Question

E. O the work done is equal to the change in themechanical energy of the object.10. Intially an object has a potential energy of 20 Jand a kinetic energy of 150 J. Under the influenceof conservative and non-conservative forcesits potential energy changed to 40 J and its kineticenergy changed to 34 J. Calculate the net work done. (1 point)A. O-118 JB. 0-115 JC. O-123 JD. 0-120 JE. O-116 J11. An object of mass 0.005 kg released froma height of 11.5 m has a speed of 6 m/s just before it4

Answer 1

Given:

The initial potential energy is P.E. = 20J

The initial kinetic energy is K.E. = 150 J

The final potential energy is P.E. ' = 40 J

The final kinetic energy is K.E.'= 34 J

To find the net work done.

Step-by-step explanation:

The net work done is given by the formula

`W\text{ =K.E.'-K.E.}`

On substituting the values, the net work done will be

`\begin{gathered} W\text{ =34-150} \\ =-116\text{ J} \end{gathered}`