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Given the function f(x)= -(x+1)^2+2. Identify the vertex and the axis of symmetry.Vertex is x = ( , )Axis of Symmetry is

Given the function f(x)= -(x+1)^2+2. Identify the vertex and the axis of symmetry-example-1
User Doilio Matsinhe
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1 Answer

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To answer this question, we will use the following graph as reference:

From the graph, we get that the vertex of the given function is:


(-1,2)\text{.}

Now, recall that the symmetry axis of a vertical parabola has equation:


x=k,

where k is the x-entry of the vertex.

Therefore, the axis of symmetry is:


x=-1.

Answer:

Vertex:


(-1,2)\text{.}

Axis of symmetry:


x=-1.

Given the function f(x)= -(x+1)^2+2. Identify the vertex and the axis of symmetry-example-1
User Dibstar
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