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The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8
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Nov 9, 2018
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The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8 4x – y = 2
Mathematics
high-school
Luigi Caradonna
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Luigi Caradonna
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hello :
the standard form of the equation for this line: x – 4y = 8
because :
the line that passes through (–4, –3) and (12, 1) :
-4-4(-3) = 8
12-4(1) = 8
Chunjw
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Nov 11, 2018
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Chunjw
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x-4y= 8
that will be the answer
JMSH
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Nov 14, 2018
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JMSH
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