Question

Find a unit vector u in the direction of v. Verify that u = 1.

Answer 1

In orde tod find the unitary vector, we need to calculate the magnitude of v. The magnitude of v is given by:

`||v||=√(0^2+(-8)^2)=8`

So, we need to divide each component of vector v by |v|:

`\begin{gathered} u=\langle(0)/(8),-(8)/(8)\rangle=\langle0,-1\rangle \\ as_{\text{ }}we_{\text{ }}can_{\text{ }}see: \\ ||u||=√(0+(-1)^2)=1 \end{gathered}`

Answer:

u = <0,-1>