190k views
4 votes
The rectangle below has an area of 15n^3+20n^7 square meters. The width of the rectangle (in meters) is equal to the greatest common monomial factor of 15n^3 and 20n^7. What is the length and width of he rectangle?

User Dinho
by
8.2k points

2 Answers

2 votes

Answer:

Length = 4n^4+3 and the width=5n^3

Explanation:

idk khan academy said so

User Arfneto
by
7.3k points
2 votes
The area (A) of a rectangular polygon is the product of the width (W) and the length (L). That is,
A = L x W

It is said in the problem that the width of the rectangle is the greatest common factor of 15n³ and 20n⁷ which is 5n³. We calculate for the length of the rectangle by dividing the given area by the width.

Length = (15n³ + 20n⁷)/(5n³)
Length = 3 + 4n⁴
User Sune Rievers
by
7.9k points