Question

Which of the following is the area of the special trapezoid if AB = 19, CD = 19, and the height is 14

Answer 1

the answer is 266 units2

Answer 2

Area of Trapezoid, having dimension, AB = 19, CD = 19, and the height is 14 is

`=(1)/(2)* [\text{Sum of parallel sides}]* [\text{Perpendicular distance between them}]\\\\=(1)/(2)*[19+19]* 14\\\\=(1)/(2)* 38* 14\\\\ =38 * 7\\\\=266`

So, Area of trapezoid = 266 cm²