resistivity Ag 15.9e-9 Ω-m resistivity Fe 100e-9 Ω-m temperature coefficient of resistivity α = 0.0038/ºC Ag R = R₀(1 + α∆T) 4*100 = 15.9(1 + (0.0038)∆T) 400/15.9 = 25 = 1 + (0.0038)∆T (0.0038)∆T = 24 ∆T = 6357ºC add 25º to get 6382ºC
I believe
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