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What is the partial pressure of carbon monoxide gas in a sealed vessel that has a total pressure of 2.68 atm and partial pressures of 1.56 atm for oxygen and 0.65 atm for carbon dioxide?

User Candiru
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2 Answers

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Pt = p1 + p2 + p3, p1 = pp (CO) atm
2.68 atm = p1 + 1.56 atm + 0.65 atm
2.68 = p1 + 2.21
p1 = 2.68 - 2.21
p1 = 0.47 atm
User Bruno Borges
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Answer: Partial pressure of CO in the sealed vessel is 0.47 atm.

Explanation: From Dalton's law of partial pressures, "Total pressure is the sum of partial pressures of the gases present in the mixture."

So, total pressure = partial pressure of carbon monoxide + partial pressure of oxygen + partial pressure of carbon dioxide

Let's plug in the values in the formula:

2.68 atm = partial pressure of CO + 1.56 atm + 0.65 atm

2.68 atm = partial pressure of CO + 2.21 atm

partial pressure of CO = 2.68 atm - 2.21 atm

partial pressure of CO = 0.47 atm

Hence, the partial pressure of carbon monoxide gas in a sealed vessel is 0.47 atm.

User GyroCocoa
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