Question

What is the y-intercept of the line that passes through the points (2,-1) and (-3,9)

Answer 1

The equation of the straight line y = -2x +3

y-intercept = 3 and m =-2

Explanation:

Step(i):-

Given that the points are ( 2,-1) and (-3,9)

The slope of the line

`m = (y_(2)-y_(1) )/(x_(2) -x_(1) ) = (9-(-1))/(-3-(2)) = (10)/(-5) = -2`

Step(ii):-

The equation of the straight line passing through the point ( 2,-1) and slope m=-2

y-y₁ = m( x- x₁)

y -(-1) = -2 ( x-2)

y +1 = -2x +4

2x +y +1-4 =0

2x +y -3 =0

Final answer:-

The equation of the straight line y = -2x +3