Question

Simplify 4 times square root 24 minus 4 square root 8 plus square root of 98.

Answer 1

`4*√(24)-4√(8)+√(98)\\\\4√(4*6)-4√(4*2)+√(49*2)\\\\4√(4)√(6)-4√(4)√(2)+√(49)√(2)\\\\4*2*√(6)-4*2*√(2)+7*√(2)\\\\8√(6)-8√(2)+7√(2)\\\\\\8√(6)-√(2)`

Answer 2

`8 *√( 6)` - 1
`√(2)`.

Explanation:

Given : 4 times square root 24 minus 4 square root 8 plus square root of 98.

To find : Simplify .

Solution : We have given statement .

According to questions :

4 times square root 24 =
`4 *√(24)`.

4 square root 8 =
`4 *√(8)`.

Square root of 98 =
`√(98)`.

Then

`4 *√(24)` -
`4 *√(8)` +
`√(98)`.

We can write 24 as 4 *6 and 8 as 4 *2 and 98 as 49 *2

`4 *√(4 * 6)` -
`4 *√(4 *2)` +
`√(49 * 2)`.

On solving square root.

`4 * 2*√( 6)` -
`4 * 2 *√(2)` + 7*
`√(2)`.

`8 *√( 6)` -
`8*√(2)` + 7*
`√(2)`.

`8 *√( 6)` - ( 8 - 7)
`√(2)`.

`8 *√( 6)` - 1
`√(2)`.

Therefore,
`8 *√( 6)` - 1
`√(2)`.