Question

HELP!!
Which expression is the cube root of -1+i
`√(3)`

Answer 1

`z^3=-1+i\sqrt3=2e^(i2\pi/3)`


`\implies z=\left(2e^(i2\pi/3)\right)^(1/3)=\begin{cases}2^(1/3)e^(i2\pi/9)\\2^(1/3)e^(i8pi/9)\\2^(1/3)e^(i14\pi/9)\end{cases}`