Question

(4x-3)÷(2x+3) + (3+2x)÷(3x^2) =2
so what can x not be

Answer 1

Remember that if an x=value makes a denominator 0, the entire equation is undefined.


`(4x-3)/(2x+3)+(3+2x)/(3x^(2))=2\\\\2x+3=0\\\\2x=-3\\\\x=(-3)/(2)\\\\\\3x^(2)=0\\\\x^(2)=0\\\\x=0`

So whenever x = -3/2 or x = 0 the equation is undefined, and that means that x cannot be -3/2 or 0.