Question

Please solve all parts of the problem and show all steps.

Answer 1

Given:

Width of the rectangle=

`w`

Length of a rectangle=

`l=w+4`

Area of the rectangle=

`A=50`

Required:

Width of the rectangle.

Answer:

Area of the rectangle=

`\begin{gathered} A=l* w \\ 50=(w+4)* w \\ 50=w^2+4w \\ w^2+4w-50=0 \\ w=(-4\pm√(16-4(1)(-50)))/(2) \\ w=(-4\pm√(16+120))/(2) \\ w=-2+3√(6,)w=-2-3√(6) \end{gathered}`

Solving this equation by quadratic equation method we get,

`w=-2+3√(6,)w=-2-3√(6)`

Final Answer:

The width of the rectangle is,

`w=-2+3√(6,)w=-2-3√(6)`