Question

If 45.6 grams of water decompose at 301 Kelvin and 1.24 atmospheres, how many liters of oxygen gas can be produced? Show all of the work used to solve this problem. 2H2O (l) yields 2H2 (g) + O2 (g)

Answer 1

45.6 g H2O(1 mol H2O/18.02g)=2.5305mol H2O
PV=nRT
(1.24)(v)=(2.5305)(.0821)(301)
v=(nRT)/P
v=(62.5345)/(1.24)
V=50.43105L H2O
50.43105L H2O(1 mol O2/2 mol H2O)
=25.2155L O2