Question

What is the empirical formula for a compound if a sample contains 1.0 g of S and 1.5g of O

Answer 1

m(S)=1 g
m(O)=1.5 g
M(S)=32 g/mol
M(O)=16 g/mol

n(S)=m(S)/M(S)
n(O)=m(O)/M(O)

n(S)=1/32=0.03125 mol
n(O)=1.5/16=0.09375 mol

S : O = 0.03125 : 0.09375 = 1 : 3

SO₃ - is the empirical formula