Question

A particle moves along the x-axis so that at time t\ge 0t≥0 its position is given by x(t)=-t^2+13t+1.x(t)=−t2+13t+1. Determine the acceleration of the particle at t=4.t=4.

Answer 1

Acceleration of the partice at t = 4 is -2

Step-by-step explanation

The acceleration of a particle is the second derivative with respect to time of the particle's position function, that is,

Acceleration = (d²x/dt²)

x (t) = -t² + 13t + 1

(dx/dt) = -2t + 13

(d²x/dt²) = -2

At t = 4,

Acceleration = (d²x/dt²) = -2

Hope this Helps!!!