Question

Find the value of the expression 2x^3+3y^2-17 when x=3 and y=4.

Answer 1

2x^3+3y^2-17 if x=3 and y=4, so we have this:
2(3)^3+3(4)^2-17
First step, I will do the exponent first.
(3)^3=27
(4)^2=16, so
2(27)+3(16)-17
=54+48-17
=102-17
=85. Hope it help!