Answer:
Transcription into mRNA strand will produce: ACU CAG CUG ACC GAC UGG CAU CUG
Translation into amino acid sequence will yield: Threonine- Glutamine- Leucine- Threonine- Aspartic acid- Tryptophan- Histidine- Leucine
Step-by-step explanation:
- Transcription is the process by which DNA template is used to synthesize a mRNA molecule in the nucleus (eukaryotes). The transcription, which is carried out by an enzyme called RNA polymerase, follows the complementary base pairing rule i.e. A-T, G-C. Note that Uracil replaces Thymine in the RNA molecule.
Based on this question in which a DNA strand was given as follows: TGA GTC GAC TGG CTG ACC GTA GAC
The mRNA strand that will result from transcribing this DNA will be: ACU CAG CUG ACC GAC UGG CAU CUG
- Translation is the process by which mRNA strand is used to synthesize amino acid sequence (protein) in the ribosomes. In the mRNA sequence, nucleotides are read in a group of three called CODONS. Each codon specifies an amino acid. Based on the mRNA sequence as follows: ACU CAG CUG ACC GAC UGG CAU CUG, the amino acid sequence that will result after using the genetic code will be: Threonine (Thr)- Glutamine (Gln)- Leucine (Leu)- Threonine (Thr)- Aspartic acid (Asp)- Tryptophan (Try)- Histidine (His)- Leucine (Leu).