Question

Consider the following balanced equation: Cu + 2AgNO3 Cu(NO3)2 + 2Ag How many moles of AgNO3 would be needed to produce 2.8 moles of Cu(NO3)2?

Answer 1

2.8(2/1)=5.6 moles of AgNO3 would be  needed

Answer 2

5.6 moles of AgNO3 is required to produce 2.8 moles of Cu(NO3)2

Step-by-step explanation:

Cu + 2AgNO3 Cu(NO3)2 + 2Ag

Before solving this one must make sure the equation is balanced. From the balance equation you could notice that the AgNo3(silver nitrate) has 2 moles while the Cu(NO3)2 has 1 mole.

If 2 moles = 1 mole

? = 2.8 moles

cross multiply 2.8 x 2 = 5.6 moles