Question

What is the net force of 10 N up and 10 N to the right?

Answer 1

14.14 N, 45° (northeast)

Explanation:

We can represent the problem as follows:

We calculate the net force as follows:

`\begin{gathered} F_N=\sqrt[]{F^2_(up)+F^2_(right)} \\ \text{ replaicng} \\ F_N=\sqrt[]{10^2+10^2} \\ F_N=\sqrt[]{100+100} \\ F_N=\sqrt[]{200}=14.14\text{ N} \end{gathered}`

Therefore, the resultant force is 14.14 N with a direction of 45°